Prime Factorization of 4,236
Answer
4,236 = 22 × 3 × 353
Step by Step Solution
| Step | Number | Divide by | Result |
|---|---|---|---|
| 1 | 4,236 | 2 | 2,118 |
| 2 | 2,118 | 2 | 1,059 |
| 3 | 1,059 | 3 | 353 |
| 4 | 353 | 353 | 1 |
Prime Factors
The prime factors of 4,236 are: 2, 3, 353
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Understanding Prime Factorization
The prime factorization of 4,236 shows how this number can be expressed as a product of prime numbers. In this case:
- We start with 4,236
- Break it down into its prime factors: 2, 3, 353
- Final expression: 22 × 3 × 353